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131403520314439 is a prime number
BaseRepresentation
bin11101111000001011000100…
…001001101000110001000111
3122020021001110021002120210221
4131320023010021220301013
5114210403402200030224
61143245535513125211
736451406505430102
oct3570130411506107
9566231407076727
10131403520314439
1138961a1359789a
12128a2a710b9807
1358423b65bbc49
142463d70133739
15102d1917c96e4
hex7782c4268c47

131403520314439 has 2 divisors, whose sum is σ = 131403520314440. Its totient is φ = 131403520314438.

The previous prime is 131403520314431. The next prime is 131403520314541. The reversal of 131403520314439 is 934413025304131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131403520314439 - 23 = 131403520314431 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131403520314395 and 131403520314404.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131403520314431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701760157219 + 65701760157220.

It is an arithmetic number, because the mean of its divisors is an integer number (65701760157220).

Almost surely, 2131403520314439 is an apocalyptic number.

131403520314439 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403520314439 is an equidigital number, since it uses as much as digits as its factorization.

131403520314439 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 466560, while the sum is 43.

The spelling of 131403520314439 in words is "one hundred thirty-one trillion, four hundred three billion, five hundred twenty million, three hundred fourteen thousand, four hundred thirty-nine".