Base | Representation |
---|---|
bin | 11101111000001011000100… |
… | …001001101000110001000111 |
3 | 122020021001110021002120210221 |
4 | 131320023010021220301013 |
5 | 114210403402200030224 |
6 | 1143245535513125211 |
7 | 36451406505430102 |
oct | 3570130411506107 |
9 | 566231407076727 |
10 | 131403520314439 |
11 | 38961a1359789a |
12 | 128a2a710b9807 |
13 | 58423b65bbc49 |
14 | 2463d70133739 |
15 | 102d1917c96e4 |
hex | 7782c4268c47 |
131403520314439 has 2 divisors, whose sum is σ = 131403520314440. Its totient is φ = 131403520314438.
The previous prime is 131403520314431. The next prime is 131403520314541. The reversal of 131403520314439 is 934413025304131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131403520314439 - 23 = 131403520314431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131403520314395 and 131403520314404.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131403520314431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701760157219 + 65701760157220.
It is an arithmetic number, because the mean of its divisors is an integer number (65701760157220).
Almost surely, 2131403520314439 is an apocalyptic number.
131403520314439 is a deficient number, since it is larger than the sum of its proper divisors (1).
131403520314439 is an equidigital number, since it uses as much as digits as its factorization.
131403520314439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 466560, while the sum is 43.
The spelling of 131403520314439 in words is "one hundred thirty-one trillion, four hundred three billion, five hundred twenty million, three hundred fourteen thousand, four hundred thirty-nine".
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