131404019004113 has 2 divisors, whose sum is σ = 131404019004114. Its totient is φ = 131404019004112.

The previous prime is 131404019004001. The next prime is 131404019004127. The reversal of 131404019004113 is 311400910404131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 65955724843969 + 65448294160144 = 8121313^2 + 8090012^2 .

It is a cyclic number.

It is not a de Polignac number, because 131404019004113 - 2¹² = 131404019000017 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131404019004113.

It is not a weakly prime, because it can be changed into another prime (131404019004163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65702009502056 + 65702009502057.

It is an arithmetic number, because the mean of its divisors is an integer number (65702009502057).

Almost surely, 2^{131404019004113} is an apocalyptic number.

It is an amenable number.

131404019004113 is a deficient number, since it is larger than the sum of its proper divisors (1).

131404019004113 is an equidigital number, since it uses as much as digits as its factorization.

131404019004113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 32.

Adding to 131404019004113 its reverse (311400910404131), we get a palindrome (442804929408244).

The spelling of 131404019004113 in words is "one hundred thirty-one trillion, four hundred four billion, nineteen million, four thousand, one hundred thirteen".