131404020121233 has 6 divisors (see below), whose sum is σ = 189805806841794. Its totient is φ = 87602680080816.

The previous prime is 131404020121223. The next prime is 131404020121261. The reversal of 131404020121233 is 332121020404131.

131404020121233 is a `hidden beast` number, since 1 + 3 + 1 + 4 + 0 + 402 + 0 + 1 + 21 + 233 = 666.

It can be written as a sum of positive squares in only one way, i.e., 119184884655489 + 12219135465744 = 10917183^2 + 3495588^2 .

It is not a de Polignac number, because 131404020121233 - 2⁴ = 131404020121217 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131404020121197 and 131404020121206.

It is not an unprimeable number, because it can be changed into a prime (131404020121223) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 7300223340060 + ... + 7300223340077.

It is an arithmetic number, because the mean of its divisors is an integer number (31634301140299).

Almost surely, 2^{131404020121233} is an apocalyptic number.

It is an amenable number.

131404020121233 is a deficient number, since it is larger than the sum of its proper divisors (58401786720561).

131404020121233 is a wasteful number, since it uses less digits than its factorization.

131404020121233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14600446680143 (or 14600446680140 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 131404020121233 its reverse (332121020404131), we get a palindrome (463525040525364).

The spelling of 131404020121233 in words is "one hundred thirty-one trillion, four hundred four billion, twenty million, one hundred twenty-one thousand, two hundred thirty-three".