131404030144307 has 4 divisors (see below), whose sum is σ = 131404088609376. Its totient is φ = 131403971679240.

The previous prime is 131404030144259. The next prime is 131404030144319. The reversal of 131404030144307 is 703441030404131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131404030144307 - 2⁶ = 131404030144243 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131404030144007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25720544 + ... + 30403197.

It is an arithmetic number, because the mean of its divisors is an integer number (32851022152344).

Almost surely, 2^{131404030144307} is an apocalyptic number.

131404030144307 is a deficient number, since it is larger than the sum of its proper divisors (58465069).

131404030144307 is an equidigital number, since it uses as much as digits as its factorization.

131404030144307 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58465068.

The product of its (nonzero) digits is 48384, while the sum is 35.

Adding to 131404030144307 its reverse (703441030404131), we get a palindrome (834845060548438).

The spelling of 131404030144307 in words is "one hundred thirty-one trillion, four hundred four billion, thirty million, one hundred forty-four thousand, three hundred seven".