131404040233 has 2 divisors, whose sum is σ = 131404040234. Its totient is φ = 131404040232.

The previous prime is 131404040227. The next prime is 131404040263. The reversal of 131404040233 is 332040404131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 85469691904 + 45934348329 = 292352^2 + 214323^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131404040233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131404040198 and 131404040207.

It is not a weakly prime, because it can be changed into another prime (131404040203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65702020116 + 65702020117.

It is an arithmetic number, because the mean of its divisors is an integer number (65702020117).

Almost surely, 2^131404040233 is an apocalyptic number.

It is an amenable number.

131404040233 is a deficient number, since it is larger than the sum of its proper divisors (1).

131404040233 is an equidigital number, since it uses as much as digits as its factorization.

131404040233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 131404040233 its reverse (332040404131), we get a palindrome (463444444364).

The spelling of 131404040233 in words is "one hundred thirty-one billion, four hundred four million, forty thousand, two hundred thirty-three".