1314041121331 has 4 divisors (see below), whose sum is σ = 1315819256200. Its totient is φ = 1312262986464.

The previous prime is 1314041121313. The next prime is 1314041121383. The reversal of 1314041121331 is 1331211404131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1314041121331 - 2³⁵ = 1279681382963 is a prime.

It is a super-2 number, since 2×1314041121331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1314041121296 and 1314041121305.

It is not an unprimeable number, because it can be changed into a prime (1314041121311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 889066326 + ... + 889067803.

It is an arithmetic number, because the mean of its divisors is an integer number (328954814050).

Almost surely, 2^{1314041121331} is an apocalyptic number.

1314041121331 is a deficient number, since it is larger than the sum of its proper divisors (1778134869).

1314041121331 is an equidigital number, since it uses as much as digits as its factorization.

1314041121331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1778134868.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 1314041121331 its reverse (1331211404131), we get a palindrome (2645252525462).

The spelling of 1314041121331 in words is "one trillion, three hundred fourteen billion, forty-one million, one hundred twenty-one thousand, three hundred thirty-one".