1314042413441 has 4 divisors (see below), whose sum is σ = 1315895788500. Its totient is φ = 1312189038384.

The previous prime is 1314042413429. The next prime is 1314042413447. The reversal of 1314042413441 is 1443142404131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 433674931600 + 880367481841 = 658540^2 + 938279^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1314042413441 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1314042413398 and 1314042413407.

It is not an unprimeable number, because it can be changed into a prime (1314042413447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 926686466 + ... + 926687883.

It is an arithmetic number, because the mean of its divisors is an integer number (328973947125).

Almost surely, 2^{1314042413441} is an apocalyptic number.

It is an amenable number.

1314042413441 is a deficient number, since it is larger than the sum of its proper divisors (1853375059).

1314042413441 is an equidigital number, since it uses as much as digits as its factorization.

1314042413441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1853375058.

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 1314042413441 its reverse (1443142404131), we get a palindrome (2757184817572).

The spelling of 1314042413441 in words is "one trillion, three hundred fourteen billion, forty-two million, four hundred thirteen thousand, four hundred forty-one".