Base | Representation |
---|---|
bin | 11101111000001011110101… |
… | …101010111000000011110011 |
3 | 122020021010121011101110000011 |
4 | 131320023311222320003303 |
5 | 114210412102341031121 |
6 | 1143250154152035351 |
7 | 36451436214201520 |
oct | 3570136552700363 |
9 | 566233534343004 |
10 | 131404351111411 |
11 | 389622aa552964 |
12 | 128a3063392b57 |
13 | 58424b97657a1 |
14 | 246400c5d8147 |
15 | 102d1de6d67e1 |
hex | 7782f5ab80f3 |
131404351111411 has 8 divisors (see below), whose sum is σ = 152638309488224. Its totient is φ = 110785869789120.
The previous prime is 131404351111339. The next prime is 131404351111489. The reversal of 131404351111411 is 114111153404131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131404351111411 - 211 = 131404351109363 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131404355111411) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 153869263170 + ... + 153869264023.
It is an arithmetic number, because the mean of its divisors is an integer number (19079788686028).
Almost surely, 2131404351111411 is an apocalyptic number.
131404351111411 is a deficient number, since it is larger than the sum of its proper divisors (21233958376813).
131404351111411 is an equidigital number, since it uses as much as digits as its factorization.
131404351111411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 307738527261.
The product of its (nonzero) digits is 2880, while the sum is 31.
The spelling of 131404351111411 in words is "one hundred thirty-one trillion, four hundred four billion, three hundred fifty-one million, one hundred eleven thousand, four hundred eleven".
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