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131404353145203 = 343801451048401
BaseRepresentation
bin11101111000001011110101…
…110010101000100101110011
3122020021010121022012202211210
4131320023311302220211303
5114210412103401121303
61143250154303411203
736451436240402115
oct3570136562504563
9566233538182753
10131404353145203
1138962300711986
12128a3063bb3b03
1358424b9cc8408
14246400c9a73b5
15102d1de989203
hex7782f5ca8973

131404353145203 has 4 divisors (see below), whose sum is σ = 175205804193608. Its totient is φ = 87602902096800.

The previous prime is 131404353145193. The next prime is 131404353145319. The reversal of 131404353145203 is 302541353404131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 131404353145203 - 216 = 131404353079667 is a prime.

It is a super-2 number, since 2×1314043531452032 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131404353845203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21900725524198 + ... + 21900725524203.

It is an arithmetic number, because the mean of its divisors is an integer number (43801451048402).

Almost surely, 2131404353145203 is an apocalyptic number.

131404353145203 is a deficient number, since it is larger than the sum of its proper divisors (43801451048405).

131404353145203 is an equidigital number, since it uses as much as digits as its factorization.

131404353145203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43801451048404.

The product of its (nonzero) digits is 259200, while the sum is 39.

The spelling of 131404353145203 in words is "one hundred thirty-one trillion, four hundred four billion, three hundred fifty-three million, one hundred forty-five thousand, two hundred three".

Divisors: 1 3 43801451048401 131404353145203