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13140542515153 = 15619841317787
BaseRepresentation
bin1011111100111000010101…
…0111100110011111010001
31201112020001000001000220111
42333032011113212133101
53210243312340441103
643540403142241321
72524241615306464
oct277160527463721
951466030030814
1013140542515153
114206966749569
121582885126241
137441bca69aa1
143360117152db
1517bc37d1d86d
hexbf3855e67d1

13140542515153 has 4 divisors (see below), whose sum is σ = 13141383848560. Its totient is φ = 13139701181748.

The previous prime is 13140542515081. The next prime is 13140542515169. The reversal of 13140542515153 is 35151524504131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13140542515153 - 225 = 13140508960721 is a prime.

It is a super-2 number, since 2×131405425151532 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13140542515853) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 420643275 + ... + 420674512.

It is an arithmetic number, because the mean of its divisors is an integer number (3285345962140).

Almost surely, 213140542515153 is an apocalyptic number.

It is an amenable number.

13140542515153 is a deficient number, since it is larger than the sum of its proper divisors (841333407).

13140542515153 is an equidigital number, since it uses as much as digits as its factorization.

13140542515153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 841333406.

The product of its (nonzero) digits is 180000, while the sum is 40.

The spelling of 13140542515153 in words is "thirteen trillion, one hundred forty billion, five hundred forty-two million, five hundred fifteen thousand, one hundred fifty-three".

Divisors: 1 15619 841317787 13140542515153