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131409431761 is a prime number
BaseRepresentation
bin111101001100010011…
…1001100110011010001
3110120012011000210112011
41322120213030303101
54123111303304021
6140211344102521
712331306511566
oct1723047146321
9416164023464
10131409431761
1150804220073
1221574904a41
13c512ba631a
14650875486d
15364196cde1
hex1e989cccd1

131409431761 has 2 divisors, whose sum is σ = 131409431762. Its totient is φ = 131409431760.

The previous prime is 131409431729. The next prime is 131409431789. The reversal of 131409431761 is 167134904131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130523238400 + 886193361 = 361280^2 + 29769^2 .

It is a cyclic number.

It is not a de Polignac number, because 131409431761 - 25 = 131409431729 is a prime.

It is a super-2 number, since 2×1314094317612 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131409431711) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65704715880 + 65704715881.

It is an arithmetic number, because the mean of its divisors is an integer number (65704715881).

Almost surely, 2131409431761 is an apocalyptic number.

It is an amenable number.

131409431761 is a deficient number, since it is larger than the sum of its proper divisors (1).

131409431761 is an equidigital number, since it uses as much as digits as its factorization.

131409431761 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54432, while the sum is 40.

The spelling of 131409431761 in words is "one hundred thirty-one billion, four hundred nine million, four hundred thirty-one thousand, seven hundred sixty-one".