Base | Representation |
---|---|
bin | 1011111100111010001101… |
… | …0001111011010011011111 |
3 | 1201112021022222022120201020 |
4 | 2333032203101323103133 |
5 | 3210300324323002111 |
6 | 43540525030215223 |
7 | 2524260220631442 |
oct | 277164321732337 |
9 | 51467288276636 |
10 | 13141044344031 |
11 | 42070a3a44a7a |
12 | 15829a51b4513 |
13 | 74426ca12456 |
14 | 33605c225659 |
15 | 17bc66de8906 |
hex | bf3a347b4df |
13141044344031 has 16 divisors (see below), whose sum is σ = 18125747378400. Its totient is φ = 8458524402048.
The previous prime is 13141044343963. The next prime is 13141044344033. The reversal of 13141044344031 is 13044344014131.
It is not a de Polignac number, because 13141044344031 - 214 = 13141044327647 is a prime.
It is a super-2 number, since 2×131410443440312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13141044343983 and 13141044344001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13141044344033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9532485 + ... + 10823601.
It is an arithmetic number, because the mean of its divisors is an integer number (1132859211150).
Almost surely, 213141044344031 is an apocalyptic number.
13141044344031 is a deficient number, since it is larger than the sum of its proper divisors (4984703034369).
13141044344031 is a wasteful number, since it uses less digits than its factorization.
13141044344031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1408138.
The product of its (nonzero) digits is 27648, while the sum is 33.
Adding to 13141044344031 its reverse (13044344014131), we get a palindrome (26185388358162).
The spelling of 13141044344031 in words is "thirteen trillion, one hundred forty-one billion, forty-four million, three hundred forty-four thousand, thirty-one".
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