13141133432051 has 2 divisors, whose sum is σ = 13141133432052. Its totient is φ = 13141133432050.

The previous prime is 13141133431999. The next prime is 13141133432177. The reversal of 13141133432051 is 15023433114131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13141133432051 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13141133431999 and 13141133432017.

It is not a weakly prime, because it can be changed into another prime (13141139432051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570566716025 + 6570566716026.

It is an arithmetic number, because the mean of its divisors is an integer number (6570566716026).

Almost surely, 2^{13141133432051} is an apocalyptic number.

13141133432051 is a deficient number, since it is larger than the sum of its proper divisors (1).

13141133432051 is an equidigital number, since it uses as much as digits as its factorization.

13141133432051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 32.

Adding to 13141133432051 its reverse (15023433114131), we get a palindrome (28164566546182).

The spelling of 13141133432051 in words is "thirteen trillion, one hundred forty-one billion, one hundred thirty-three million, four hundred thirty-two thousand, fifty-one".