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131412120001 = 181172563291
BaseRepresentation
bin111101001100011000…
…1011101000111000001
3110120012100002101002121
41322120301131013001
54123113000320001
6140211521444241
712331341406201
oct1723061350701
9416170071077
10131412120001
1150805796858
12215757a0681
13c513607ab6
146508c54401
153641cee6a1
hex1e98c5d1c1

131412120001 has 4 divisors (see below), whose sum is σ = 131484685104. Its totient is φ = 131339554900.

The previous prime is 131412119987. The next prime is 131412120029. The reversal of 131412120001 is 100021214131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131412120001 - 231 = 129264636353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131412120031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36279835 + ... + 36283456.

It is an arithmetic number, because the mean of its divisors is an integer number (32871171276).

Almost surely, 2131412120001 is an apocalyptic number.

It is an amenable number.

131412120001 is a deficient number, since it is larger than the sum of its proper divisors (72565103).

131412120001 is an equidigital number, since it uses as much as digits as its factorization.

131412120001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72565102.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 131412120001 its reverse (100021214131), we get a palindrome (231433334132).

The spelling of 131412120001 in words is "one hundred thirty-one billion, four hundred twelve million, one hundred twenty thousand, one".

Divisors: 1 1811 72563291 131412120001