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131412133441 = 137119584431
BaseRepresentation
bin111101001100011000…
…1100000011001000001
3110120012100010001112101
41322120301200121001
54123113001232231
6140211522030401
712331341463321
oct1723061403101
9416170101471
10131412133441
11508057a5966
12215757a8401
13c513610c54
146508c59281
153641d03661
hex1e98c60641

131412133441 has 4 divisors (see below), whose sum is σ = 131421731584. Its totient is φ = 131402535300.

The previous prime is 131412133439. The next prime is 131412133451. The reversal of 131412133441 is 144331214131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131412133441 - 21 = 131412133439 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131412133451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4778505 + ... + 4805926.

It is an arithmetic number, because the mean of its divisors is an integer number (32855432896).

Almost surely, 2131412133441 is an apocalyptic number.

It is an amenable number.

131412133441 is a deficient number, since it is larger than the sum of its proper divisors (9598143).

131412133441 is an equidigital number, since it uses as much as digits as its factorization.

131412133441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9598142.

The product of its digits is 3456, while the sum is 28.

Adding to 131412133441 its reverse (144331214131), we get a palindrome (275743347572).

The spelling of 131412133441 in words is "one hundred thirty-one billion, four hundred twelve million, one hundred thirty-three thousand, four hundred forty-one".

Divisors: 1 13711 9584431 131412133441