Base | Representation |
---|---|
bin | 1011111100111010111001… |
… | …0111000101000101110011 |
3 | 1201112021210221010021211002 |
4 | 2333032232113011011303 |
5 | 3210301214420303321 |
6 | 43540555310512215 |
7 | 2524264636022456 |
oct | 277165627050563 |
9 | 51467727107732 |
10 | 13141230244211 |
11 | 4207189977593 |
12 | 1582a3750566b |
13 | 74429c3a0a64 |
14 | 336078bb749d |
15 | 17bc783ba20b |
hex | bf3ae5c5173 |
13141230244211 has 4 divisors (see below), whose sum is σ = 13141287462672. Its totient is φ = 13141173025752.
The previous prime is 13141230244187. The next prime is 13141230244229. The reversal of 13141230244211 is 11244203214131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13141230244211 - 230 = 13140156502387 is a prime.
It is a super-3 number, since 3×131412302442113 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13141232244211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28263335 + ... + 28724528.
It is an arithmetic number, because the mean of its divisors is an integer number (3285321865668).
Almost surely, 213141230244211 is an apocalyptic number.
13141230244211 is a deficient number, since it is larger than the sum of its proper divisors (57218461).
13141230244211 is an equidigital number, since it uses as much as digits as its factorization.
13141230244211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57218460.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 13141230244211 its reverse (11244203214131), we get a palindrome (24385433458342).
The spelling of 13141230244211 in words is "thirteen trillion, one hundred forty-one billion, two hundred thirty million, two hundred forty-four thousand, two hundred eleven".
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