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131412321200449 is a prime number
BaseRepresentation
bin11101111000010011010000…
…101110010110100101000001
3122020021220011121111220210001
4131320103100232112211001
5114211024413211403244
61143253553102440001
736452140552633642
oct3570232056264501
9566256147456701
10131412321200449
113896571a450803
12128a4708593001
135843189a352c3
142464566d176c9
15102d5092745d4
hex7784d0b96941

131412321200449 has 2 divisors, whose sum is σ = 131412321200450. Its totient is φ = 131412321200448.

The previous prime is 131412321200411. The next prime is 131412321200533. The reversal of 131412321200449 is 944002123214131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 90616406140225 + 40795915060224 = 9519265^2 + 6387168^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131412321200449 is a prime.

It is not a weakly prime, because it can be changed into another prime (131412391200449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706160600224 + 65706160600225.

It is an arithmetic number, because the mean of its divisors is an integer number (65706160600225).

Almost surely, 2131412321200449 is an apocalyptic number.

It is an amenable number.

131412321200449 is a deficient number, since it is larger than the sum of its proper divisors (1).

131412321200449 is an equidigital number, since it uses as much as digits as its factorization.

131412321200449 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 37.

The spelling of 131412321200449 in words is "one hundred thirty-one trillion, four hundred twelve billion, three hundred twenty-one million, two hundred thousand, four hundred forty-nine".