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131412333157577 is a prime number
BaseRepresentation
bin11101111000010011010001…
…011011111101110011001001
3122020021220012110000101212122
4131320103101123331303021
5114211024424242020302
61143253554211021025
736452141056364243
oct3570232133756311
9566256173011778
10131412333157577
113896572617832a
12128a471059a775
13584318c360924
14246456874b093
15102d50a3373a2
hex7784d16fdcc9

131412333157577 has 2 divisors, whose sum is σ = 131412333157578. Its totient is φ = 131412333157576.

The previous prime is 131412333157513. The next prime is 131412333157597. The reversal of 131412333157577 is 775751333214131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82358964633856 + 49053368523721 = 9075184^2 + 7003811^2 .

It is a cyclic number.

It is not a de Polignac number, because 131412333157577 - 26 = 131412333157513 is a prime.

It is a super-2 number, since 2×1314123331575772 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131412333157597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706166578788 + 65706166578789.

It is an arithmetic number, because the mean of its divisors is an integer number (65706166578789).

Almost surely, 2131412333157577 is an apocalyptic number.

It is an amenable number.

131412333157577 is a deficient number, since it is larger than the sum of its proper divisors (1).

131412333157577 is an equidigital number, since it uses as much as digits as its factorization.

131412333157577 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5556600, while the sum is 53.

The spelling of 131412333157577 in words is "one hundred thirty-one trillion, four hundred twelve billion, three hundred thirty-three million, one hundred fifty-seven thousand, five hundred seventy-seven".