Base | Representation |
---|---|
bin | 11101111000010011010001… |
… | …011111101010000001001011 |
3 | 122020021220012111211120002222 |
4 | 131320103101133222001023 |
5 | 114211024430014001011 |
6 | 1143253554243444255 |
7 | 36452141100534143 |
oct | 3570232137520113 |
9 | 566256174746088 |
10 | 131412334125131 |
11 | 38965726779264 |
12 | 128a471098668b |
13 | 584318c60c147 |
14 | 246456891d923 |
15 | 102d50a478ddb |
hex | 7784d17ea04b |
131412334125131 has 2 divisors, whose sum is σ = 131412334125132. Its totient is φ = 131412334125130.
The previous prime is 131412334125077. The next prime is 131412334125229. The reversal of 131412334125131 is 131521433214131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131412334125131 - 26 = 131412334125067 is a prime.
It is a super-2 number, since 2×1314123341251312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131412334125091 and 131412334125100.
It is not a weakly prime, because it can be changed into another prime (131412334127131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706167062565 + 65706167062566.
It is an arithmetic number, because the mean of its divisors is an integer number (65706167062566).
Almost surely, 2131412334125131 is an apocalyptic number.
131412334125131 is a deficient number, since it is larger than the sum of its proper divisors (1).
131412334125131 is an equidigital number, since it uses as much as digits as its factorization.
131412334125131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 25920, while the sum is 35.
Adding to 131412334125131 its reverse (131521433214131), we get a palindrome (262933767339262).
The spelling of 131412334125131 in words is "one hundred thirty-one trillion, four hundred twelve billion, three hundred thirty-four million, one hundred twenty-five thousand, one hundred thirty-one".
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