Base | Representation |
---|---|
bin | 11101111000010011111111… |
… | …001010000011010001001011 |
3 | 122020021222011220100212112201 |
4 | 131320103333022003101023 |
5 | 114211033012123311243 |
6 | 1143254202251421031 |
7 | 36452166062300335 |
oct | 3570237712032113 |
9 | 566258156325481 |
10 | 131413100213323 |
11 | 38965a8a1576a5 |
12 | 128a48a5454777 |
13 | 584328224a676 |
14 | 24645dc57c455 |
15 | 102d55285304d |
hex | 7784ff28344b |
131413100213323 has 2 divisors, whose sum is σ = 131413100213324. Its totient is φ = 131413100213322.
The previous prime is 131413100213303. The next prime is 131413100213441. The reversal of 131413100213323 is 323312001314131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131413100213323 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131413100213291 and 131413100213300.
It is not a weakly prime, because it can be changed into another prime (131413100213303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706550106661 + 65706550106662.
It is an arithmetic number, because the mean of its divisors is an integer number (65706550106662).
Almost surely, 2131413100213323 is an apocalyptic number.
131413100213323 is a deficient number, since it is larger than the sum of its proper divisors (1).
131413100213323 is an equidigital number, since it uses as much as digits as its factorization.
131413100213323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 28.
Adding to 131413100213323 its reverse (323312001314131), we get a palindrome (454725101527454).
The spelling of 131413100213323 in words is "one hundred thirty-one trillion, four hundred thirteen billion, one hundred million, two hundred thirteen thousand, three hundred twenty-three".
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