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131413313013443 = 971354776422819
BaseRepresentation
bin11101111000010100001011…
…110101110100011011000011
3122020021222201201210020102122
4131320110023311310123003
5114211033431112412233
61143254235332434455
736452204255126006
oct3570241365643303
9566258651706378
10131413313013443
113896608929256a
12128a4944778a2b
1358432b7366bb6
14246461c93353d
15102d566389d98
hex77850bd746c3

131413313013443 has 4 divisors (see below), whose sum is σ = 132768089436360. Its totient is φ = 130058536590528.

The previous prime is 131413313013439. The next prime is 131413313013503. The reversal of 131413313013443 is 344310313314131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131413313013443 - 22 = 131413313013439 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131413313010443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 677388211313 + ... + 677388211506.

It is an arithmetic number, because the mean of its divisors is an integer number (33192022359090).

Almost surely, 2131413313013443 is an apocalyptic number.

131413313013443 is a deficient number, since it is larger than the sum of its proper divisors (1354776422917).

131413313013443 is an equidigital number, since it uses as much as digits as its factorization.

131413313013443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1354776422916.

The product of its (nonzero) digits is 46656, while the sum is 35.

Adding to 131413313013443 its reverse (344310313314131), we get a palindrome (475723626327574).

The spelling of 131413313013443 in words is "one hundred thirty-one trillion, four hundred thirteen billion, three hundred thirteen million, thirteen thousand, four hundred forty-three".

Divisors: 1 97 1354776422819 131413313013443