Base | Representation |
---|---|
bin | 11101111000010100001011… |
… | …110111000100101000111011 |
3 | 122020021222201202101221010211 |
4 | 131320110023313010220323 |
5 | 114211033431203421021 |
6 | 1143254235343451551 |
7 | 36452204260664641 |
oct | 3570241367045073 |
9 | 566258652357124 |
10 | 131413313342011 |
11 | 38966089497408 |
12 | 128a49448b6bb7 |
13 | 58432b745060c |
14 | 246461c9bb191 |
15 | 102d5664023e1 |
hex | 77850bdc4a3b |
131413313342011 has 4 divisors (see below), whose sum is σ = 131413350223800. Its totient is φ = 131413276460224.
The previous prime is 131413313341951. The next prime is 131413313342023. The reversal of 131413313342011 is 110243313314131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131413313342011 - 235 = 131378953603643 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131413313342611) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12446806 + ... + 20438923.
It is an arithmetic number, because the mean of its divisors is an integer number (32853337555950).
Almost surely, 2131413313342011 is an apocalyptic number.
131413313342011 is a deficient number, since it is larger than the sum of its proper divisors (36881789).
131413313342011 is an equidigital number, since it uses as much as digits as its factorization.
131413313342011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36881788.
The product of its (nonzero) digits is 7776, while the sum is 31.
Adding to 131413313342011 its reverse (110243313314131), we get a palindrome (241656626656142).
The spelling of 131413313342011 in words is "one hundred thirty-one trillion, four hundred thirteen billion, three hundred thirteen million, three hundred forty-two thousand, eleven".
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