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131413640051 = 271484921181
BaseRepresentation
bin111101001100011011…
…1010000001101110011
3110120012102221121012202
41322120313100031303
54123113342440201
6140212014213415
712331360336631
oct1723067201563
9416172847182
10131413640051
11508066348a1
12215761b426b
13c513a1a935
14650912c351
153641eeec6b
hex1e98dd0373

131413640051 has 4 divisors (see below), whose sum is σ = 131898561504. Its totient is φ = 130928718600.

The previous prime is 131413640047. The next prime is 131413640093. The reversal of 131413640051 is 150046314131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131413640051 - 22 = 131413640047 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131413639996 and 131413640023.

It is not an unprimeable number, because it can be changed into a prime (131413640951) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 242460320 + ... + 242460861.

It is an arithmetic number, because the mean of its divisors is an integer number (32974640376).

Almost surely, 2131413640051 is an apocalyptic number.

131413640051 is a deficient number, since it is larger than the sum of its proper divisors (484921453).

131413640051 is an equidigital number, since it uses as much as digits as its factorization.

131413640051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 484921452.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 131413640051 its reverse (150046314131), we get a palindrome (281459954182).

The spelling of 131413640051 in words is "one hundred thirty-one billion, four hundred thirteen million, six hundred forty thousand, fifty-one".

Divisors: 1 271 484921181 131413640051