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131414301433 = 1271996151839
BaseRepresentation
bin111101001100011100…
…1110001101011111001
3110120012111012012110101
41322120321301223321
54123114030121213
6140212040315401
712331366063102
oct1723071615371
9416174165411
10131414301433
1150806a46798
1221576472b61
13c513bbc99c
1465092613a9
1536420d0bdd
hex1e98e71af9

131414301433 has 8 divisors (see below), whose sum is σ = 132458250240. Its totient is φ = 130370496480.

The previous prime is 131414301427. The next prime is 131414301443. The reversal of 131414301433 is 334103414131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131414301433 - 217 = 131414170361 is a prime.

It is a super-2 number, since 2×1314143014332 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131414301443) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2509128 + ... + 2560966.

It is an arithmetic number, because the mean of its divisors is an integer number (16557281280).

Almost surely, 2131414301433 is an apocalyptic number.

It is an amenable number.

131414301433 is a deficient number, since it is larger than the sum of its proper divisors (1043948807).

131414301433 is a wasteful number, since it uses less digits than its factorization.

131414301433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71927.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 131414301433 its reverse (334103414131), we get a palindrome (465517715564).

The spelling of 131414301433 in words is "one hundred thirty-one billion, four hundred fourteen million, three hundred one thousand, four hundred thirty-three".

Divisors: 1 127 19961 51839 2535047 6583553 1034758279 131414301433