Base | Representation |
---|---|
bin | 1011111100111011101111… |
… | …0010000010001111011001 |
3 | 1201112022101121211010000112 |
4 | 2333032323302002033121 |
5 | 3210302200041223413 |
6 | 43541033513014105 |
7 | 2524303341651026 |
oct | 277167362021731 |
9 | 51468347733015 |
10 | 13141455414233 |
11 | 4207294a91113 |
12 | 1582a9a9b4335 |
13 | 744306c2b763 |
14 | 33609aa6c54d |
15 | 17bc8d0472a8 |
hex | bf3bbc823d9 |
13141455414233 has 2 divisors, whose sum is σ = 13141455414234. Its totient is φ = 13141455414232.
The previous prime is 13141455414119. The next prime is 13141455414281. The reversal of 13141455414233 is 33241455414131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8517974962249 + 4623480451984 = 2918557^2 + 2150228^2 .
It is a cyclic number.
It is not a de Polignac number, because 13141455414233 - 226 = 13141388305369 is a prime.
It is not a weakly prime, because it can be changed into another prime (13141455414293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570727707116 + 6570727707117.
It is an arithmetic number, because the mean of its divisors is an integer number (6570727707117).
Almost surely, 213141455414233 is an apocalyptic number.
It is an amenable number.
13141455414233 is a deficient number, since it is larger than the sum of its proper divisors (1).
13141455414233 is an equidigital number, since it uses as much as digits as its factorization.
13141455414233 is an evil number, because the sum of its binary digits is even.
The product of its digits is 345600, while the sum is 41.
The spelling of 13141455414233 in words is "thirteen trillion, one hundred forty-one billion, four hundred fifty-five million, four hundred fourteen thousand, two hundred thirty-three".
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