Base | Representation |
---|---|
bin | 1011111100111101111010… |
… | …1000001000110001101011 |
3 | 1201112100220100212021021121 |
4 | 2333033132220020301223 |
5 | 3210304344221201443 |
6 | 43541211515120111 |
7 | 2524324001022145 |
oct | 277173650106153 |
9 | 51470810767247 |
10 | 13142040022123 |
11 | 4207564a86731 |
12 | 1583022743037 |
13 | 74439b09839c |
14 | 336114569c95 |
15 | 17bcc45244ed |
hex | bf3dea08c6b |
13142040022123 has 4 divisors (see below), whose sum is σ = 13148331091720. Its totient is φ = 13135748952528.
The previous prime is 13142040022121. The next prime is 13142040022151. The reversal of 13142040022123 is 32122004024131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13142040022123 - 21 = 13142040022121 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13142040022121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3145531665 + ... + 3145535842.
It is an arithmetic number, because the mean of its divisors is an integer number (3287082772930).
Almost surely, 213142040022123 is an apocalyptic number.
13142040022123 is a deficient number, since it is larger than the sum of its proper divisors (6291069597).
13142040022123 is an equidigital number, since it uses as much as digits as its factorization.
13142040022123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6291069596.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 13142040022123 its reverse (32122004024131), we get a palindrome (45264044046254).
The spelling of 13142040022123 in words is "thirteen trillion, one hundred forty-two billion, forty million, twenty-two thousand, one hundred twenty-three".
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