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13142044024121 is a prime number
BaseRepresentation
bin1011111100111101111011…
…0111011001110100111001
31201112100220122101120222202
42333033132313121310321
53210304401232232441
643541212140555545
72524324050030605
oct277173667316471
951470818346882
1013142044024121
11420756726a471
121583023b52bb5
1374439bb69b2c
14336114ccc505
1517bcc4a6519b
hexbf3dedd9d39

13142044024121 has 2 divisors, whose sum is σ = 13142044024122. Its totient is φ = 13142044024120.

The previous prime is 13142044024117. The next prime is 13142044024177. The reversal of 13142044024121 is 12142044024131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8951585286400 + 4190458737721 = 2991920^2 + 2047061^2 .

It is a cyclic number.

It is not a de Polignac number, because 13142044024121 - 22 = 13142044024117 is a prime.

It is a super-2 number, since 2×131420440241212 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13142044054121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571022012060 + 6571022012061.

It is an arithmetic number, because the mean of its divisors is an integer number (6571022012061).

Almost surely, 213142044024121 is an apocalyptic number.

It is an amenable number.

13142044024121 is a deficient number, since it is larger than the sum of its proper divisors (1).

13142044024121 is an equidigital number, since it uses as much as digits as its factorization.

13142044024121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 13142044024121 its reverse (12142044024131), we get a palindrome (25284088048252).

The spelling of 13142044024121 in words is "thirteen trillion, one hundred forty-two billion, forty-four million, twenty-four thousand, one hundred twenty-one".