1314213332017 has 2 divisors, whose sum is σ = 1314213332018. Its totient is φ = 1314213332016.

The previous prime is 1314213331999. The next prime is 1314213332027. The reversal of 1314213332017 is 7102333124131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1271844873121 + 42368458896 = 1127761^2 + 205836^2 .

It is a cyclic number.

It is not a de Polignac number, because 1314213332017 - 2¹¹ = 1314213329969 is a prime.

It is a super-3 number, since 3×1314213332017³ (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1314213332017.

It is not a weakly prime, because it can be changed into another prime (1314213332027) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657106666008 + 657106666009.

It is an arithmetic number, because the mean of its divisors is an integer number (657106666009).

Almost surely, 2^{1314213332017} is an apocalyptic number.

It is an amenable number.

1314213332017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314213332017 is an equidigital number, since it uses as much as digits as its factorization.

1314213332017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9072, while the sum is 31.

Adding to 1314213332017 its reverse (7102333124131), we get a palindrome (8416546456148).

The spelling of 1314213332017 in words is "one trillion, three hundred fourteen billion, two hundred thirteen million, three hundred thirty-two thousand, seventeen".