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1314221131 is a prime number
BaseRepresentation
bin100111001010101…
…0110110001001011
310101120221100110201
41032111112301023
510142420034011
6334224153031
744365460326
oct11625266113
93346840421
101314221131
11614930873
12308168777
1317c376c52
14c67837bd
157a59dcc1
hex4e556c4b

1314221131 has 2 divisors, whose sum is σ = 1314221132. Its totient is φ = 1314221130.

The previous prime is 1314221123. The next prime is 1314221137. The reversal of 1314221131 is 1311224131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1314221131 - 23 = 1314221123 is a prime.

It is a super-2 number, since 2×13142211312 = 3454354362333838322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1314221099 and 1314221108.

It is not a weakly prime, because it can be changed into another prime (1314221137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657110565 + 657110566.

It is an arithmetic number, because the mean of its divisors is an integer number (657110566).

Almost surely, 21314221131 is an apocalyptic number.

1314221131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314221131 is an equidigital number, since it uses as much as digits as its factorization.

1314221131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 144, while the sum is 19.

The square root of 1314221131 is about 36252.1879477639. The cubic root of 1314221131 is about 1095.3581617161.

Adding to 1314221131 its reverse (1311224131), we get a palindrome (2625445262).

The spelling of 1314221131 in words is "one billion, three hundred fourteen million, two hundred twenty-one thousand, one hundred thirty-one".