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131422324152001 is a prime number
BaseRepresentation
bin11101111000011100100100…
…111100100101011011000001
3122020022211222201211111200011
4131320130210330211123001
5114211210404440331001
61143302325432424521
736452643464421001
oct3570344474453301
9566284881744604
10131422324152001
11389699928a1313
12128a663a548141
1358440c221704c
142464c35608001
15102d8e2516d51
hex778724f256c1

131422324152001 has 2 divisors, whose sum is σ = 131422324152002. Its totient is φ = 131422324152000.

The previous prime is 131422324151977. The next prime is 131422324152017. The reversal of 131422324152001 is 100251423224131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83292363396225 + 48129960755776 = 9126465^2 + 6937576^2 .

It is an emirp because it is prime and its reverse (100251423224131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131422324152001 - 217 = 131422324020929 is a prime.

It is not a weakly prime, because it can be changed into another prime (131422324159001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65711162076000 + 65711162076001.

It is an arithmetic number, because the mean of its divisors is an integer number (65711162076001).

Almost surely, 2131422324152001 is an apocalyptic number.

It is an amenable number.

131422324152001 is a deficient number, since it is larger than the sum of its proper divisors (1).

131422324152001 is an equidigital number, since it uses as much as digits as its factorization.

131422324152001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 131422324152001 its reverse (100251423224131), we get a palindrome (231673747376132).

The spelling of 131422324152001 in words is "one hundred thirty-one trillion, four hundred twenty-two billion, three hundred twenty-four million, one hundred fifty-two thousand, one".