Base | Representation |
---|---|
bin | 11101111000011100101011… |
… | …110111110010001100101001 |
3 | 122020022212021211110011120122 |
4 | 131320130223313302030221 |
5 | 114211211124211142441 |
6 | 1143302345142533025 |
7 | 36452646405101246 |
oct | 3570345367621451 |
9 | 566285254404518 |
10 | 131422440334121 |
11 | 38969a424356a2 |
12 | 128a6671437175 |
13 | 5844110305271 |
14 | 2464c46c0c5cd |
15 | 102d8ec81634b |
hex | 77872bdf2329 |
131422440334121 has 2 divisors, whose sum is σ = 131422440334122. Its totient is φ = 131422440334120.
The previous prime is 131422440334111. The next prime is 131422440334151. The reversal of 131422440334121 is 121433044224131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 92318679444121 + 39103760890000 = 9608261^2 + 6253300^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131422440334121 is a prime.
It is not a weakly prime, because it can be changed into another prime (131422440334111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65711220167060 + 65711220167061.
It is an arithmetic number, because the mean of its divisors is an integer number (65711220167061).
Almost surely, 2131422440334121 is an apocalyptic number.
It is an amenable number.
131422440334121 is a deficient number, since it is larger than the sum of its proper divisors (1).
131422440334121 is an equidigital number, since it uses as much as digits as its factorization.
131422440334121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 131422440334121 its reverse (121433044224131), we get a palindrome (252855484558252).
The spelling of 131422440334121 in words is "one hundred thirty-one trillion, four hundred twenty-two billion, four hundred forty million, three hundred thirty-four thousand, one hundred twenty-one".
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