Base | Representation |
---|---|
bin | 10011000111111110000… |
… | …000000100010111111001 |
3 | 11122122020200221022010001 |
4 | 103013332000010113321 |
5 | 133013013433043212 |
6 | 2443425225553001 |
7 | 163643520362554 |
oct | 23077600042771 |
9 | 4578220838101 |
10 | 1314226456057 |
11 | 4673a6633199 |
12 | 192857945761 |
13 | 96c145c4488 |
14 | 47874b6d69b |
15 | 242bcd8b657 |
hex | 131fe0045f9 |
1314226456057 has 2 divisors, whose sum is σ = 1314226456058. Its totient is φ = 1314226456056.
The previous prime is 1314226456043. The next prime is 1314226456093. The reversal of 1314226456057 is 7506546224131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 831116662336 + 483109793721 = 911656^2 + 695061^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1314226456057 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1314226455998 and 1314226456016.
It is not a weakly prime, because it can be changed into another prime (1314226456027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657113228028 + 657113228029.
It is an arithmetic number, because the mean of its divisors is an integer number (657113228029).
Almost surely, 21314226456057 is an apocalyptic number.
It is an amenable number.
1314226456057 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314226456057 is an equidigital number, since it uses as much as digits as its factorization.
1314226456057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1209600, while the sum is 46.
The spelling of 1314226456057 in words is "one trillion, three hundred fourteen billion, two hundred twenty-six million, four hundred fifty-six thousand, fifty-seven".
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