13142303134033 has 4 divisors (see below), whose sum is σ = 13390271117748. Its totient is φ = 12894335150320.

The previous prime is 13142303133991. The next prime is 13142303134057. The reversal of 13142303134033 is 33043130324131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10597056217344 + 2545246916689 = 3255312^2 + 1595383^2 .

It is a cyclic number.

It is not a de Polignac number, because 13142303134033 - 2¹³ = 13142303125841 is a prime.

It is a super-2 number, since 2×13142303134033² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13142303133986 and 13142303134004.

It is not an unprimeable number, because it can be changed into a prime (13142303134063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 123983991778 + ... + 123983991883.

It is an arithmetic number, because the mean of its divisors is an integer number (3347567779437).

Almost surely, 2^{13142303134033} is an apocalyptic number.

It is an amenable number.

13142303134033 is a deficient number, since it is larger than the sum of its proper divisors (247967983715).

13142303134033 is an equidigital number, since it uses as much as digits as its factorization.

13142303134033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 247967983714.

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 13142303134033 its reverse (33043130324131), we get a palindrome (46185433458164).

The spelling of 13142303134033 in words is "thirteen trillion, one hundred forty-two billion, three hundred three million, one hundred thirty-four thousand, thirty-three".