131423114342081 has 2 divisors, whose sum is σ = 131423114342082. Its totient is φ = 131423114342080.

The previous prime is 131423114341993. The next prime is 131423114342101. The reversal of 131423114342081 is 180243411324131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130439812050625 + 983302291456 = 11421025^2 + 991616^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131423114342081 is a prime.

It is a super-2 number, since 2×131423114342081² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131423114942081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65711557171040 + 65711557171041.

It is an arithmetic number, because the mean of its divisors is an integer number (65711557171041).

Almost surely, 2^{131423114342081} is an apocalyptic number.

It is an amenable number.

131423114342081 is a deficient number, since it is larger than the sum of its proper divisors (1).

131423114342081 is an equidigital number, since it uses as much as digits as its factorization.

131423114342081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 55296, while the sum is 38.

The spelling of 131423114342081 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, one hundred fourteen million, three hundred forty-two thousand, eighty-one".