131423131401041 has 2 divisors, whose sum is σ = 131423131401042. Its totient is φ = 131423131401040.

The previous prime is 131423131401031. The next prime is 131423131401101. The reversal of 131423131401041 is 140104131324131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 116904966307600 + 14518165093441 = 10812260^2 + 3810271^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131423131401041 is a prime.

It is a super-3 number, since 3×131423131401041³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131423131400995 and 131423131401013.

It is not a weakly prime, because it can be changed into another prime (131423131401031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65711565700520 + 65711565700521.

It is an arithmetic number, because the mean of its divisors is an integer number (65711565700521).

Almost surely, 2^{131423131401041} is an apocalyptic number.

It is an amenable number.

131423131401041 is a deficient number, since it is larger than the sum of its proper divisors (1).

131423131401041 is an equidigital number, since it uses as much as digits as its factorization.

131423131401041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 131423131401041 its reverse (140104131324131), we get a palindrome (271527262725172).

The spelling of 131423131401041 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, one hundred thirty-one million, four hundred one thousand, forty-one".