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131423131421209 is a prime number
BaseRepresentation
bin11101111000011101010101…
…000100000100101000011001
3122020022221001222212000211201
4131320131111010010220121
5114211214033120434314
61143302541511154201
736453002466201355
oct3570352504045031
9566287058760751
10131423131421209
113896a267547651
12128a6824975961
1358441c0543834
142464cb0906465
15102d93d327b74
hex778755104a19

131423131421209 has 2 divisors, whose sum is σ = 131423131421210. Its totient is φ = 131423131421208.

The previous prime is 131423131421201. The next prime is 131423131421227. The reversal of 131423131421209 is 902124131324131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 83262029788809 + 48161101632400 = 9124803^2 + 6939820^2 .

It is an emirp because it is prime and its reverse (902124131324131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131423131421209 - 23 = 131423131421201 is a prime.

It is not a weakly prime, because it can be changed into another prime (131423131421201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65711565710604 + 65711565710605.

It is an arithmetic number, because the mean of its divisors is an integer number (65711565710605).

Almost surely, 2131423131421209 is an apocalyptic number.

It is an amenable number.

131423131421209 is a deficient number, since it is larger than the sum of its proper divisors (1).

131423131421209 is an equidigital number, since it uses as much as digits as its factorization.

131423131421209 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 37.

The spelling of 131423131421209 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, one hundred thirty-one million, four hundred twenty-one thousand, two hundred nine".