Base | Representation |
---|---|
bin | 11101111000011101010101… |
… | …110000010100011000001011 |
3 | 122020022221002210200022110011 |
4 | 131320131111300110120023 |
5 | 114211214044103120133 |
6 | 1143302543003532351 |
7 | 36453002666610250 |
oct | 3570352560243013 |
9 | 566287083608404 |
10 | 131423143020043 |
11 | 3896a273049a66 |
12 | 128a682882a0b7 |
13 | 58441c2a75054 |
14 | 2464cb2285427 |
15 | 102d93e3696cd |
hex | 778755c1460b |
131423143020043 has 16 divisors (see below), whose sum is σ = 155433507119104. Its totient is φ = 108739992667680.
The previous prime is 131423143020007. The next prime is 131423143020107. The reversal of 131423143020043 is 340020341324131.
It is a cyclic number.
It is not a de Polignac number, because 131423143020043 - 233 = 131414553085451 is a prime.
It is a super-2 number, since 2×1314231430200432 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131423143019987 and 131423143020014.
It is not an unprimeable number, because it can be changed into a prime (131423143020343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 762680355 + ... + 762852652.
It is an arithmetic number, because the mean of its divisors is an integer number (9714594194944).
Almost surely, 2131423143020043 is an apocalyptic number.
131423143020043 is a deficient number, since it is larger than the sum of its proper divisors (24010364099061).
131423143020043 is a wasteful number, since it uses less digits than its factorization.
131423143020043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1525533442.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 131423143020043 its reverse (340020341324131), we get a palindrome (471443484344174).
The spelling of 131423143020043 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, one hundred forty-three million, twenty thousand, forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.198 sec. • engine limits •