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1314231545113 is a prime number
BaseRepresentation
bin10011000111111110010…
…011011110110100011001
311122122021001111211222121
4103013332103132310121
5133013021233420423
62443425531021241
7163643611546504
oct23077623366431
94578231454877
101314231545113
114673a9499723
1219285959a821
1396c15686956
14478756d613b
15242bd54445d
hex131fe4ded19

1314231545113 has 2 divisors, whose sum is σ = 1314231545114. Its totient is φ = 1314231545112.

The previous prime is 1314231545051. The next prime is 1314231545119. The reversal of 1314231545113 is 3115451324131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1192173545689 + 122057999424 = 1091867^2 + 349368^2 .

It is a cyclic number.

It is not a de Polignac number, because 1314231545113 - 29 = 1314231544601 is a prime.

It is not a weakly prime, because it can be changed into another prime (1314231545119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657115772556 + 657115772557.

It is an arithmetic number, because the mean of its divisors is an integer number (657115772557).

Almost surely, 21314231545113 is an apocalyptic number.

It is an amenable number.

1314231545113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314231545113 is an equidigital number, since it uses as much as digits as its factorization.

1314231545113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 21600, while the sum is 34.

Adding to 1314231545113 its reverse (3115451324131), we get a palindrome (4429682869244).

The spelling of 1314231545113 in words is "one trillion, three hundred fourteen billion, two hundred thirty-one million, five hundred forty-five thousand, one hundred thirteen".