Base | Representation |
---|---|
bin | 11101111000011101011010… |
… | …010111101000010101111101 |
3 | 122020022221022012100100211220 |
4 | 131320131122113220111331 |
5 | 114211214223412344201 |
6 | 1143302554411103553 |
7 | 36453004626613635 |
oct | 3570353227502575 |
9 | 566287265310756 |
10 | 131423220434301 |
11 | 3896a302814494 |
12 | 128a684a741bb9 |
13 | 5844205b0b4c3 |
14 | 2464cbc6776c5 |
15 | 102d94605c036 |
hex | 77875a5e857d |
131423220434301 has 16 divisors (see below), whose sum is σ = 176207514345408. Its totient is φ = 87127249708800.
The previous prime is 131423220434269. The next prime is 131423220434323. The reversal of 131423220434301 is 103434022324131.
It is not a de Polignac number, because 131423220434301 - 25 = 131423220434269 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131423220434501) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5596981 + ... + 17151461.
It is an arithmetic number, because the mean of its divisors is an integer number (11012969646588).
Almost surely, 2131423220434301 is an apocalyptic number.
It is an amenable number.
131423220434301 is a deficient number, since it is larger than the sum of its proper divisors (44784293911107).
131423220434301 is a wasteful number, since it uses less digits than its factorization.
131423220434301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11575612.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 131423220434301 its reverse (103434022324131), we get a palindrome (234857242758432).
The spelling of 131423220434301 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, two hundred twenty million, four hundred thirty-four thousand, three hundred one".
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