Base | Representation |
---|---|
bin | 11000011110101100… |
… | …00011011101001011 |
3 | 1020220220122010020002 |
4 | 30033112003131023 |
5 | 203403414411301 |
6 | 10012033553215 |
7 | 643452026201 |
oct | 141726033513 |
9 | 36826563202 |
10 | 13142341451 |
11 | 5634566718 |
12 | 266941580b |
13 | 1315a1ba05 |
14 | 8c961d071 |
15 | 51dbbc16b |
hex | 30f58374b |
13142341451 has 2 divisors, whose sum is σ = 13142341452. Its totient is φ = 13142341450.
The previous prime is 13142341409. The next prime is 13142341573. The reversal of 13142341451 is 15414324131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13142341451 - 210 = 13142340427 is a prime.
It is a super-2 number, since 2×131423414512 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (13142344451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571170725 + 6571170726.
It is an arithmetic number, because the mean of its divisors is an integer number (6571170726).
Almost surely, 213142341451 is an apocalyptic number.
13142341451 is a deficient number, since it is larger than the sum of its proper divisors (1).
13142341451 is an equidigital number, since it uses as much as digits as its factorization.
13142341451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5760, while the sum is 29.
Adding to 13142341451 its reverse (15414324131), we get a palindrome (28556665582).
The spelling of 13142341451 in words is "thirteen billion, one hundred forty-two million, three hundred forty-one thousand, four hundred fifty-one".
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