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131424113203 = 311422585573
BaseRepresentation
bin111101001100101111…
…1001101001000110011
3110120020011122200200021
41322121133031020303
54123124033110303
6140213030504311
712331545346615
oct1723137151063
9416204580607
10131424113203
1150811538499
1221579805097
13c515c46976
14650a696db5
153642dbcebd
hex1e997cd233

131424113203 has 4 divisors (see below), whose sum is σ = 131846699088. Its totient is φ = 131001527320.

The previous prime is 131424113201. The next prime is 131424113207. The reversal of 131424113203 is 302311424131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 302311424131 = 425281710851.

It is a cyclic number.

It is not a de Polignac number, because 131424113203 - 21 = 131424113201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131424113201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211292476 + ... + 211293097.

It is an arithmetic number, because the mean of its divisors is an integer number (32961674772).

Almost surely, 2131424113203 is an apocalyptic number.

131424113203 is a deficient number, since it is larger than the sum of its proper divisors (422585885).

131424113203 is an equidigital number, since it uses as much as digits as its factorization.

131424113203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 422585884.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 131424113203 its reverse (302311424131), we get a palindrome (433735537334).

The spelling of 131424113203 in words is "one hundred thirty-one billion, four hundred twenty-four million, one hundred thirteen thousand, two hundred three".

Divisors: 1 311 422585573 131424113203