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131424125153 = 281467701513
BaseRepresentation
bin111101001100101111…
…1010000000011100001
3110120020011200022001212
41322121133100003201
54123124034001103
6140213031035505
712331545426506
oct1723137200341
9416204608055
10131424125153
1150811546472
122157980bb95
13c515c4c239
14650a69b4ad
153642dc17d8
hex1e997d00e1

131424125153 has 4 divisors (see below), whose sum is σ = 131891826948. Its totient is φ = 130956423360.

The previous prime is 131424125111. The next prime is 131424125167. The reversal of 131424125153 is 351521424131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 51723495184 + 79700629969 = 227428^2 + 282313^2 .

It is a cyclic number.

It is not a de Polignac number, because 131424125153 - 26 = 131424125089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131424185153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 233850476 + ... + 233851037.

It is an arithmetic number, because the mean of its divisors is an integer number (32972956737).

Almost surely, 2131424125153 is an apocalyptic number.

It is an amenable number.

131424125153 is a deficient number, since it is larger than the sum of its proper divisors (467701795).

131424125153 is an equidigital number, since it uses as much as digits as its factorization.

131424125153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 467701794.

The product of its digits is 14400, while the sum is 32.

Adding to 131424125153 its reverse (351521424131), we get a palindrome (482945549284).

The spelling of 131424125153 in words is "one hundred thirty-one billion, four hundred twenty-four million, one hundred twenty-five thousand, one hundred fifty-three".

Divisors: 1 281 467701513 131424125153