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13142414401 = 29274490063
BaseRepresentation
bin11000011110101100…
…10101010001000001
31020220220202211021221
430033112111101001
5203403424230101
610012035315041
7643452451654
oct141726252101
936826684257
1013142414401
115634606506
12266944ba81
131315a45c8c
148c963b89b
1551dbd3aa1
hex30f595441

13142414401 has 4 divisors (see below), whose sum is σ = 13146907392. Its totient is φ = 13137921412.

The previous prime is 13142414377. The next prime is 13142414423. The reversal of 13142414401 is 10441424131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10441424131 = 43242823817.

It is a cyclic number.

It is not a de Polignac number, because 13142414401 - 27 = 13142414273 is a prime.

It is a super-2 number, since 2×131424144012 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13142414491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2242105 + ... + 2247958.

It is an arithmetic number, because the mean of its divisors is an integer number (3286726848).

Almost surely, 213142414401 is an apocalyptic number.

It is an amenable number.

13142414401 is a deficient number, since it is larger than the sum of its proper divisors (4492991).

13142414401 is an equidigital number, since it uses as much as digits as its factorization.

13142414401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4492990.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 13142414401 its reverse (10441424131), we get a palindrome (23583838532).

The spelling of 13142414401 in words is "thirteen billion, one hundred forty-two million, four hundred fourteen thousand, four hundred one".

Divisors: 1 2927 4490063 13142414401