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131424201123 = 31923100247293
BaseRepresentation
bin111101001100101111…
…1100010100110100011
3110120020011211011021120
41322121133202212203
54123124043413443
6140213032423323
712331546164135
oct1723137424643
9416204734246
10131424201123
1150811598556
1221579847b43
13c515c779a7
14650a6bb055
153642dd9083
hex1e997e29a3

131424201123 has 16 divisors (see below), whose sum is σ = 192474804480. Its totient is φ = 79395855264.

The previous prime is 131424201121. The next prime is 131424201127. The reversal of 131424201123 is 321102424131.

It is not a de Polignac number, because 131424201123 - 21 = 131424201121 is a prime.

It is a super-2 number, since 2×1314242011232 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131424201093 and 131424201102.

It is not an unprimeable number, because it can be changed into a prime (131424201121) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 50122336 + ... + 50124957.

It is an arithmetic number, because the mean of its divisors is an integer number (12029675280).

Almost surely, 2131424201123 is an apocalyptic number.

131424201123 is a deficient number, since it is larger than the sum of its proper divisors (61050603357).

131424201123 is a wasteful number, since it uses less digits than its factorization.

131424201123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100247338.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 131424201123 its reverse (321102424131), we get a palindrome (452526625254).

The spelling of 131424201123 in words is "one hundred thirty-one billion, four hundred twenty-four million, two hundred one thousand, one hundred twenty-three".

Divisors: 1 3 19 23 57 69 437 1311 100247293 300741879 1904698567 2305687739 5714095701 6917063217 43808067041 131424201123