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13142421330043 is a prime number
BaseRepresentation
bin1011111100111111010101…
…0110101101100001111011
31201112101212221100201102011
42333033311112231201323
53210311134330030133
643541313415550351
72524336311053065
oct277176526554173
951471787321364
1013142421330043
114207740244a45
12158310a38b3b7
1374442c093985
1433614d066735
1517bce7c446cd
hexbf3f55ad87b

13142421330043 has 2 divisors, whose sum is σ = 13142421330044. Its totient is φ = 13142421330042.

The previous prime is 13142421329963. The next prime is 13142421330131. The reversal of 13142421330043 is 34003312424131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13142421330043 - 213 = 13142421321851 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13142421329987 and 13142421330014.

It is not a weakly prime, because it can be changed into another prime (13142421330343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571210665021 + 6571210665022.

It is an arithmetic number, because the mean of its divisors is an integer number (6571210665022).

Almost surely, 213142421330043 is an apocalyptic number.

13142421330043 is a deficient number, since it is larger than the sum of its proper divisors (1).

13142421330043 is an equidigital number, since it uses as much as digits as its factorization.

13142421330043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 13142421330043 its reverse (34003312424131), we get a palindrome (47145733754174).

The spelling of 13142421330043 in words is "thirteen trillion, one hundred forty-two billion, four hundred twenty-one million, three hundred thirty thousand, forty-three".