13142443411 has 4 divisors (see below), whose sum is σ = 13144363024. Its totient is φ = 13140523800.

The previous prime is 13142443361. The next prime is 13142443429. The reversal of 13142443411 is 11434424131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13142443411 - 2¹¹ = 13142441363 is a prime.

It is a super-2 number, since 2×13142443411² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13142443411.

It is not an unprimeable number, because it can be changed into a prime (13142443451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 949500 + ... + 963241.

It is an arithmetic number, because the mean of its divisors is an integer number (3286090756).

Almost surely, 2^13142443411 is an apocalyptic number.

13142443411 is a deficient number, since it is larger than the sum of its proper divisors (1919613).

13142443411 is an equidigital number, since it uses as much as digits as its factorization.

13142443411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1919612.

The product of its digits is 4608, while the sum is 28.

Adding to 13142443411 its reverse (11434424131), we get a palindrome (24576867542).

The spelling of 13142443411 in words is "thirteen billion, one hundred forty-two million, four hundred forty-three thousand, four hundred eleven".