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13142455410521 is a prime number
BaseRepresentation
bin1011111100111111011101…
…1000101101111101011001
31201112101222022111012001002
42333033313120231331121
53210311222041114041
643541321034234345
72524340203535063
oct277176730557531
951471868435032
1013142455410521
114207758502128
1215831198859b5
13744436167038
143361537b8733
1517bceac2759b
hexbf3f762df59

13142455410521 has 2 divisors, whose sum is σ = 13142455410522. Its totient is φ = 13142455410520.

The previous prime is 13142455410509. The next prime is 13142455410527. The reversal of 13142455410521 is 12501455424131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9353437438921 + 3789017971600 = 3058339^2 + 1946540^2 .

It is a cyclic number.

It is not a de Polignac number, because 13142455410521 - 226 = 13142388301657 is a prime.

It is a super-3 number, since 3×131424554105213 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13142455410527) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571227705260 + 6571227705261.

It is an arithmetic number, because the mean of its divisors is an integer number (6571227705261).

Almost surely, 213142455410521 is an apocalyptic number.

It is an amenable number.

13142455410521 is a deficient number, since it is larger than the sum of its proper divisors (1).

13142455410521 is an equidigital number, since it uses as much as digits as its factorization.

13142455410521 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96000, while the sum is 38.

The spelling of 13142455410521 in words is "thirteen trillion, one hundred forty-two billion, four hundred fifty-five million, four hundred ten thousand, five hundred twenty-one".