Base | Representation |
---|---|
bin | 10011000111111111100… |
… | …110001111111011000011 |
3 | 11122122022120100011120220 |
4 | 103013333212033323003 |
5 | 133013042312221201 |
6 | 2443432024034123 |
7 | 163644264144051 |
oct | 23077746177303 |
9 | 4578276304526 |
10 | 1314253242051 |
11 | 46740a768982 |
12 | 192864902943 |
13 | 96c1a012589 |
14 | 478785431d1 |
15 | 242c03cd036 |
hex | 131ff98fec3 |
1314253242051 has 4 divisors (see below), whose sum is σ = 1752337656072. Its totient is φ = 876168828032.
The previous prime is 1314253242017. The next prime is 1314253242089. The reversal of 1314253242051 is 1502423524131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1314253242051 - 217 = 1314253110979 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1314253246051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219042207006 + ... + 219042207011.
It is an arithmetic number, because the mean of its divisors is an integer number (438084414018).
Almost surely, 21314253242051 is an apocalyptic number.
1314253242051 is a deficient number, since it is larger than the sum of its proper divisors (438084414021).
1314253242051 is an equidigital number, since it uses as much as digits as its factorization.
1314253242051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 438084414020.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 1314253242051 its reverse (1502423524131), we get a palindrome (2816676766182).
The spelling of 1314253242051 in words is "one trillion, three hundred fourteen billion, two hundred fifty-three million, two hundred forty-two thousand, fifty-one".
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