1314303121 has 4 divisors (see below), whose sum is σ = 1314406512. Its totient is φ = 1314199732.

The previous prime is 1314303119. The next prime is 1314303181. The reversal of 1314303121 is 1213034131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 1213034131 = 1619 ⋅749249.

It is a cyclic number.

It is not a de Polignac number, because 1314303121 - 2¹ = 1314303119 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1314303181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29431 + ... + 59116.

It is an arithmetic number, because the mean of its divisors is an integer number (328601628).

Almost surely, 2^1314303121 is an apocalyptic number.

It is an amenable number.

1314303121 is a deficient number, since it is larger than the sum of its proper divisors (103391).

1314303121 is an equidigital number, since it uses as much as digits as its factorization.

1314303121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 103390.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 1314303121 is about 36253.3187584254. The cubic root of 1314303121 is about 1095.3809398585.

Adding to 1314303121 its reverse (1213034131), we get a palindrome (2527337252).

The spelling of 1314303121 in words is "one billion, three hundred fourteen million, three hundred three thousand, one hundred twenty-one".