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1314304133411 = 2834644184217
BaseRepresentation
bin10011001000000010101…
…000011000100100100011
311122122110010002201102002
4103020002220120210203
5133013143324232121
62443441042514215
7163645452543263
oct23100250304443
94578403081362
101314304133411
11467436468355
1219287996596b
1396c277205c9
14478811cd7a3
15242c4ad1e0b
hex13202a18923

1314304133411 has 4 divisors (see below), whose sum is σ = 1318948317912. Its totient is φ = 1309659948912.

The previous prime is 1314304133393. The next prime is 1314304133447. The reversal of 1314304133411 is 1143314034131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1314304133411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1314304132411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2322091826 + ... + 2322092391.

It is an arithmetic number, because the mean of its divisors is an integer number (329737079478).

Almost surely, 21314304133411 is an apocalyptic number.

1314304133411 is a deficient number, since it is larger than the sum of its proper divisors (4644184501).

1314304133411 is an equidigital number, since it uses as much as digits as its factorization.

1314304133411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4644184500.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 1314304133411 its reverse (1143314034131), we get a palindrome (2457618167542).

The spelling of 1314304133411 in words is "one trillion, three hundred fourteen billion, three hundred four million, one hundred thirty-three thousand, four hundred eleven".

Divisors: 1 283 4644184217 1314304133411